3x^2+11x+1=-7+x

Solution for 3x^2+11x+1=-7+x equation:

3x^2+11x+1=-7+x

We move all terms to the left:

3x^2+11x+1-(-7+x)=0

We add all the numbers together, and all the variables

3x^2+11x-(x-7)+1=0

We get rid of parentheses

3x^2+11x-x+7+1=0

We add all the numbers together, and all the variables

3x^2+10x+8=0

a = 3; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·3·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*3}=\frac{-8}{6}
=-1+1/3
$